C & C++: Faust's problem

• martin_ambuhl / 200 / Wed, 24 Jun 2009 08:28:00 GMT / Comments (0)
• > #include
  > #define d b%a
  > #define e a%b
  This is already a bad start.
  > void main()
  And this is worse: it's not even valid C. The rest of your program
  looks like very bad Basic. Try this on for size:
  
  #include
  #include
  
  int gcdx(int x, int y)
  {
  int rem = x % y;
  return !rem ? y : gcdx(y, rem);
  }
  
  int gcd(int x, int y)
  {
  if (x < 0)
  x = -x;
  if (y < 0)
  y = -y;
  if (x < y) {
  int t;
  t = x;
  x = y;
  y = t;
  }
  return gcdx(x, y);
  }
  
  int main()
  {
  int first, second, nread;
  char input[BUFSIZ];
  printf
  ("This program will figure out the greatest common\n"
  "divisor in two numbers you give.\n");
  printf("Please enter the numbers.\n");
  if (!fgets(input, sizeof input, stdin))
  exit(EXIT_FAILURE);
  if (2 != (nread = sscanf(input, "%d%d", &first, &second))) {
  if (1 != nread) {
  printf("Oh, jeez!\n");
  exit(EXIT_FAILURE);
  }
  printf("OK, that's one. Give me another one.\n");
  if (!fgets(input, sizeof input, stdin))
  exit(EXIT_FAILURE);
  if (1 != (nread = sscanf(input, "%d", &second))) {
  printf("You don't want to play? Ok.\n");
  exit(EXIT_FAILURE);
  }
  }
  printf("The GCD is %d\n", gcd(first, second));
  }
• Keywords:

  faust, c++

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